n^2+2n+4=

Solution for n^2+2n+4= equation:

Simplifying
n2 + 2n + 4 = 0

Reorder the terms:
4 + 2n + n2 = 0

Solving
4 + 2n + n2 = 0

Solving for variable 'n'.

Begin completing the square.

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + 2n + -4 + n2 = 0 + -4

Reorder the terms:
4 + -4 + 2n + n2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 2n + n2 = 0 + -4
2n + n2 = 0 + -4

Combine like terms: 0 + -4 = -4
2n + n2 = -4

The n term is 2n.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2n + 1 + n2 = -4 + 1

Reorder the terms:
1 + 2n + n2 = -4 + 1

Combine like terms: -4 + 1 = -3
1 + 2n + n2 = -3

Factor a perfect square on the left side:
(n + 1)(n + 1) = -3

Can't calculate square root of the right side.

The solution to this equation could not be determined.